I'm given data on Newton's Law of Cooling, the formula is:
T(s)= (To - m)*B^t+m
I'm given some data with time intervals 5 seconds apart, I have to create an equation using y=A(B^x) with newton's law of cooling.
I hope you're with me so far. So I understand everything above this, in order to find A and B I have to linearize the data by using ln. But it's not linear, I DONT UNDERSTAND!!!!!!!!!1
I don't understand why it's not linearizing, i'm doing exactly the opposite of an exponentional function by doing a natural log of it, and it's not freaking linear.
I know once I linearize that I have to take the e^(slope of linearized data) and that will be my B value.
So I need help understanding why this shit isn't linear. thanks thanks xoxoxxxo yours truly :wub:
T(s)= (To - m)*B^t+m
I'm given some data with time intervals 5 seconds apart, I have to create an equation using y=A(B^x) with newton's law of cooling.
I hope you're with me so far. So I understand everything above this, in order to find A and B I have to linearize the data by using ln. But it's not linear, I DONT UNDERSTAND!!!!!!!!!1
I don't understand why it's not linearizing, i'm doing exactly the opposite of an exponentional function by doing a natural log of it, and it's not freaking linear.
I know once I linearize that I have to take the e^(slope of linearized data) and that will be my B value.
So I need help understanding why this shit isn't linear. thanks thanks xoxoxxxo yours truly :wub:
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