who is sarien

[Nickname]

way to go, now Stul is going to cry.

[D1st0rt]

he has apparently never heard of order of operations

[Rudy]

Feel free to post in one of the many other Sarien/DangerGirl threads currently littered throughout the forums on this same topic.
I don't want to see another new thread on this issue or it will be treated as a copycat thread and merged/deleted or whatever.
Alrighty?

[Money]

SOUNDS GOOD m8

[suxxor]

You broke math.

Let a and b be any two distinct numbers. a = b + c for some nonzero c.

(a-b)a = (a-b)(b+c)
a^2 - ba = ab - b^2 + ac - bc
a^2 - ba - ac = ab - b^2 - bc
a(a - b - c) = b(a - b - c)
a = b

Therefore, any two distinct numbers are, in fact equal. By extension, all numbers are equal.

[Troll King]

That would work if you hadn't divided both sides of the equation by zero.

[Money]

Fuck Math

[suxxor]

Man, you had to go and spoil it for everyone. The above "proof" and the "Where'd the extra dollar go?" riddle are two of my favorite abuses of math.

[Worr]

It's DoCk>

Where is DoCk>?

[Clichy]

Where is DoCk>?

He's playing aliased under the name of Izor

[PrOnEsSim]

2:Bullet> who did he trade it to?
2:cripple> zidane
2:Bullet> whos that?
2:cripple> some newb
2:Chaos> some newbie
2:X`terrania> some newb
2:calm> some newb
2:TiQ> some newb
2:JBM> some newb

nn2 chat is full of douches.

[deathking]

Let a and b be any two distinct numbers. a = b + c for some nonzero c.

(a-b)a = (a-b)(b+c)
a^2 - ba = ab - b^2 + ac - bc
a^2 - ba - ac = ab - b^2 - bc
a(a - b - c) = b(a - b - c)
a = b

Therefore, any two distinct numbers are, in fact equal. By extension, all numbers are equal.

WTF are u talking about. a=b+c, thus, a-b-c=0. any numbers multiplied by zero is zero x(0)=y(0). nice try. Guess it takes more than u to break math